Geometric series: \(\displaystyle\sum_{n=0}^{\infty}ar^n=\frac{a}{1-r}\) for \(|r|<1\) Taylor: \(f(x)=\sum_{n=0}^{\infty}\frac{f^{(n)}(a)}{n!}(x-a)^n\)
MEMORIZE
\(e^x=\sum\frac{x^n}{n!}\), \(\sin x=\sum\frac{(-1)^n x^{2n+1}}{(2n+1)!}\), \(\cos x=\sum\frac{(-1)^n x^{2n}}{(2n)!}\), \(\frac{1}{1-x}=\sum x^n\)
PARAMETRIC If \(x=x(t),\,y=y(t)\): \(\dfrac{dy}{dx}=\dfrac{dy/dt}{dx/dt}\),
Arc length \(=\int_a^b\!\sqrt{\left(\tfrac{dx}{dt}\right)^2+\left(\tfrac{dy}{dt}\right)^2}\,dt\)
POLAR Area \(=\dfrac{1}{2}\int_\alpha^\beta[r(\theta)]^2\,d\theta\)
EXAMPLE
Find the 3rd-degree Taylor polynomial for \(e^x\) centered at 0.
Answer: \(1+x+\dfrac{x^2}{2}+\dfrac{x^3}{6}\)