📐 Concept Review & Key Formulae
Arithmetic Sequences & Series
aₙ = a₁ + (n−1)d
Sₙ = n/2 · (2a₁ + (n−1)d)
d = common difference. S₁₀ with a₁=3, d=4: S₁₀ = 5·(6+36) = 210
Geometric Sequences & Series
aₙ = a₁ · rⁿ⁻¹
S∞ = a₁/(1−r), |r| < 1
r = common ratio. Converges only when |r| < 1.
Exponents & Logarithms
logₐ(xy) = logₐx + logₐy
logₐ(xⁿ) = n·logₐx
Key identity: a^(log_a x) = x. Change of base: log_b(x) = ln(x)/ln(b)
Quadratic Functions
f(x) = ax² + bx + c
vertex: x = −b/(2a)
Discriminant Δ = b²−4ac. Two real roots ↔ Δ > 0.
Binomial Theorem
(a+b)ⁿ = Σ C(n,r)·aⁿ⁻ʳ·bʳ
C(n,r) = n! / (r!(n−r)!)
The coefficient of xʳ term: C(n,r)·(coeff of x)ʳ·(const)ⁿ⁻ʳ
Differentiation
d/dx[xⁿ] = nxⁿ⁻¹
Chain rule: d/dx[f(g(x))] = f'(g(x))·g'(x)
Product rule: (uv)' = u'v + uv'. Quotient: (u/v)' = (u'v−uv')/v²
Integration
∫xⁿ dx = xⁿ⁺¹/(n+1) + C
∫ₐᵇ f(x)dx = F(b) − F(a)
Area between curves: ∫|f(x)−g(x)|dx. Always find antiderivative first.
Trigonometry
Sine rule: a/sinA = b/sinB
Cosine rule: c²=a²+b²−2ab·cosC
Exact values: sin30°=½, sin45°=√2/2, sin60°=√3/2, cos60°=½
Probability
P(A∪B) = P(A)+P(B)−P(A∩B)
P(A|B) = P(A∩B)/P(B)
Independent events: P(A∩B) = P(A)·P(B). Mutually exclusive: P(A∩B)=0.
Normal Distribution & Statistics
Z = (X − μ) / σ
X ~ N(μ, σ²)
68% of data within 1σ, 95% within 2σ, 99.7% within 3σ of mean.
Vectors
a · b = |a||b|cosθ
a · b = a₁b₁ + a₂b₂ (+ a₃b₃)
Perpendicular ↔ a·b = 0. |a| = √(a₁²+a₂²). Parallel ↔ a = kb.
Exponential Models
N(t) = N₀ · e^(kt)
Half-life: t = ln(2)/k
k > 0: growth. k < 0: decay. To find t, isolate eˢᵒᵐᵉᵗʰⁱⁿᵍ, then take ln.
📋 Worked Example — Exam Technique
Find the sum of the first 8 terms of the arithmetic sequence 5, 9, 13, …
a₁ = 5, d = 4, n = 8
S₈ = 8/2 · (2·5 + 7·4) = 4 · (10 + 28) = 4 · 38 = 152
Find the coefficient of x² in the expansion of (3x + 2)⁴.
r = 2: C(4,2)·(3x)²·2² = 6 · 9x² · 4 = 216x² → coefficient = 216
The arithmetic sequence has first term \(a_1 = 3\) and common difference \(d = 4\).
Find \(S_{10}\), the sum of the first 10 terms.
✦ Worked Solution
Use \(S_n = \frac{n}{2}(2a_1 + (n-1)d)\)
\(S_{10} = \frac{10}{2}(2 \cdot 3 + 9 \cdot 4) = 5(6 + 36) = 5 \times 42\)
Answer: C — \(S_{10} = 210\)
A geometric sequence has first term \(a_1 = 2\) and common ratio \(r = 3\).
Find the 5th term \(a_5\).
✦ Worked Solution
Use \(a_n = a_1 \cdot r^{n-1}\)
\(a_5 = 2 \cdot 3^{4} = 2 \cdot 81 = 162\)
Answer: B — \(a_5 = 162\)
Evaluate \(\log_2 32\).
✦ Worked Solution
We need \(x\) such that \(2^x = 32\)
\(32 = 2^5\), so \(\log_2 32 = 5\)
Answer: B — \(\log_2 32 = 5\)
Find the coordinates of the vertex of \(f(x) = x^2 - 6x + 8\).
A \((3,\ -1)\)
B \((3,\ 1)\)
C \((-3,\ -1)\)
D \((6,\ 8)\)
✦ Worked Solution
Vertex x-coordinate: \(x = \dfrac{-b}{2a} = \dfrac{6}{2} = 3\)
\(f(3) = 9 - 18 + 8 = -1\)
Answer: A — Vertex at \((3,\ -1)\)
Find the coefficient of \(x^3\) in the expansion of \((2x + 1)^5\).
✦ Worked Solution
The \(x^3\) term uses \(r = 3\) (power of \(2x\) is 3):
\(\binom{5}{3}(2x)^3(1)^2 = 10 \cdot 8x^3 \cdot 1 = 80x^3\)
Answer: B — coefficient of \(x^3\) is 80
Given \(f(x) = 3x^4 - 2x^2 + 5\), find \(f'(1)\).
✦ Worked Solution
\(f'(x) = 12x^3 - 4x\)
\(f'(1) = 12(1)^3 - 4(1) = 12 - 4 = 8\)
Answer: C — \(f'(1) = 8\)
Evaluate \(\displaystyle\int_0^3 (2x + 1)\,dx\).
✦ Worked Solution
Antiderivative: \(F(x) = x^2 + x\)
\(F(3) - F(0) = (9 + 3) - (0 + 0) = 12\)
Answer: D — the integral equals 12
Find the exact value of \(\sin 60°\).
A \(\dfrac{1}{2}\)
B \(\dfrac{\sqrt{2}}{2}\)
C \(\dfrac{\sqrt{3}}{2}\)
D \(\dfrac{\sqrt{3}}{3}\)
✦ Worked Solution
From the 30-60-90 triangle: sides are 1, √3, 2
\(\sin 60° = \dfrac{\text{opposite}}{\text{hypotenuse}} = \dfrac{\sqrt{3}}{2}\)
Answer: C — \(\sin 60° = \dfrac{\sqrt{3}}{2}\)
In triangle \(ABC\), side \(a = 8\), angle \(A = 30°\), and angle \(B = 45°\).
Find the length of side \(b\).
A \(4\sqrt{2}\)
B \(8\sqrt{2}\)
C \(4\sqrt{3}\)
D \(8\sqrt{3}\)
✦ Worked Solution
Sine rule: \(\dfrac{b}{\sin B} = \dfrac{a}{\sin A}\)
\(b = \dfrac{8 \sin 45°}{\sin 30°} = \dfrac{8 \cdot \tfrac{\sqrt{2}}{2}}{\tfrac{1}{2}} = 8\sqrt{2}\)
Answer: B — \(b = 8\sqrt{2}\)
Events \(A\) and \(B\) have \(P(A) = 0.4\), \(P(B) = 0.5\), and \(P(A \cap B) = 0.2\).
Find \(P(A \cup B)\).
✦ Worked Solution
Addition rule: \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\)
\(= 0.4 + 0.5 - 0.2 = 0.7\)
Answer: C — \(P(A \cup B) = 0.7\)
The marks in an exam are normally distributed with mean \(\mu = 70\) and standard deviation \(\sigma = 5\).
A student scores 75. Find the standardised score (\(z\)-score).
✦ Worked Solution
\(z = \dfrac{X - \mu}{\sigma} = \dfrac{75 - 70}{5} = \dfrac{5}{5} = 1\)
Answer: B — \(z = 1\)
Find the scalar (dot) product of vectors \(\mathbf{a} = \begin{pmatrix}3\\4\end{pmatrix}\) and \(\mathbf{b} = \begin{pmatrix}1\\-2\end{pmatrix}\).
A \(-5\)
B \(5\)
C \(-11\)
D \(11\)
✦ Worked Solution
\(\mathbf{a} \cdot \mathbf{b} = (3)(1) + (4)(-2) = 3 - 8 = -5\)
Answer: A — dot product is \(-5\)
Let \(f(x) = 2x + 1\) and \(g(x) = x^2\). Find \(f(g(3))\).
✦ Worked Solution
First compute \(g(3) = 3^2 = 9\)
Then \(f(g(3)) = f(9) = 2(9) + 1 = 19\)
Answer: C — \(f(g(3)) = 19\)
Simplify \(\log_6 4 + \log_6 9\).
✦ Worked Solution
\(\log_6 4 + \log_6 9 = \log_6(4 \times 9) = \log_6 36\)
\(36 = 6^2\), so \(\log_6 36 = 2\)
Answer: B — the expression equals 2
For what values of \(k\) does \(f(x) = x^2 - 5x + k\) have two distinct real roots?
A \(k > \dfrac{25}{4}\)
B \(k = \dfrac{25}{4}\)
C \(k < \dfrac{25}{4}\)
D \(k < 5\)
✦ Worked Solution
Two distinct real roots require discriminant \(\Delta > 0\)
\(\Delta = b^2 - 4ac = 25 - 4k > 0 \implies k < \dfrac{25}{4}\)
Answer: C — \(k < \dfrac{25}{4}\)
Given \(y = (2x + 1)^3\), find \(\dfrac{dy}{dx}\) at \(x = 1\).
✦ Worked Solution
Chain rule: \(\dfrac{dy}{dx} = 3(2x+1)^2 \cdot 2 = 6(2x+1)^2\)
At \(x=1\): \(6(2+1)^2 = 6 \times 9 = 54\)
Answer: B — \(\dfrac{dy}{dx}\bigg|_{x=1} = 54\)
Evaluate \(\displaystyle\int_1^4 (3x^2 - 2x)\,dx\).
✦ Worked Solution
Antiderivative: \(F(x) = x^3 - x^2\)
\(F(4) - F(1) = (64 - 16) - (1 - 1) = 48 - 0 = 48\)
Answer: C — the integral equals 48
In triangle \(ABC\), \(a = 5\), \(b = 7\), and angle \(C = 60°\). Find the length of side \(c\).
A \(\sqrt{34}\)
B \(\sqrt{39}\)
C \(\sqrt{49}\)
D \(\sqrt{74}\)
✦ Worked Solution
\(c^2 = a^2 + b^2 - 2ab\cos C = 25 + 49 - 2(5)(7)\cos 60°\)
\(= 74 - 70 \times \dfrac{1}{2} = 74 - 35 = 39\)
Answer: B — \(c = \sqrt{39}\)
\(X \sim B(5,\ 0.3)\). Find \(P(X = 2)\), giving your answer to 4 significant figures.
A 0.1323
B 0.2268
C 0.3087
D 0.3602
✦ Worked Solution
\(P(X=2) = \binom{5}{2}(0.3)^2(0.7)^3\)
\(= 10 \times 0.09 \times 0.343 = 0.3087\)
Answer: C — \(P(X=2) = 0.3087\)
A radioactive substance decays according to \(N(t) = 200\,e^{-0.05t}\).
Find the time \(t\) (in years) when \(N = 100\). Give your answer to 2 decimal places.
A \(t = 10.00\)
B \(t = 12.50\)
C \(t = 13.86\)
D \(t = 15.00\)
✦ Worked Solution
\(100 = 200\,e^{-0.05t} \implies e^{-0.05t} = 0.5\)
\(-0.05t = \ln(0.5) \implies t = \dfrac{-\ln 0.5}{0.05} = \dfrac{\ln 2}{0.05} \approx 13.86\)
Answer: C — \(t \approx 13.86\) years
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