🎯 Official Practice Exam

Precalculus
Master Exam

20 essential multiple-choice problems across all core Precalculus topics — exam-style, expert-verified.

📚 20 Questions
⏱ 25 Minutes
🏆 Exam Style
✅ Verified Answers
📚 Key Concepts & Formulas to Memorize
Unit 1
Functions & Domain
Dom(√f) : f(x) ≥ 0
Dom(1/f) : f(x) ≠ 0
Find where the expression is defined. Combine both restrictions when both apply.
Unit 2
Composition & Inverse
(f∘g)(x) = f(g(x))
f⁻¹: swap x↔y, solve y
Always apply inner function first. Verify: f(f⁻¹(x)) = x.
Unit 3
Polynomial Zeros
Vieta's: sum = −b/a
product = c/a (quadratic)
For xⁿ + bxⁿ⁻¹ + …, sum of roots = −b.
Unit 4
Rational Functions
VA: denominator = 0
Hole: common factor cancels
Always factor and cancel common factors first before finding asymptotes.
Unit 5
Exponential Laws
aˣ = aʸ ⟹ x = y
8 = 2³, 9 = 3², 27 = 3³
Convert all bases to the same prime base to equate exponents.
Unit 6
Logarithm Rules
log(ab) = log a + log b
log(aⁿ) = n·log a
logₐa = 1
Combine logs before solving. Always check domain (argument > 0).
Unit 7
Trig Exact Values
sin30°=½, cos60°=½
sin45°=cos45°=√2/2
sin60°=√3/2
Use sum/difference formulas for non-standard angles like 75°, 15°.
Unit 8
Trig Equations
sin θ = k ⟹
θ = arcsin(k) + 2πn
or π − arcsin(k) + 2πn
Factor trig equations like quadratics. Find all solutions in [0, 2π).
Unit 9
Law of Cosines
c² = a² + b² − 2ab·cos C
Use when given SAS or SSS. Law of Sines for AAS or ASA.
Unit 10
Sequences & Series
Arithmetic: aₙ = a₁+(n−1)d
Sₙ = n(a₁+aₙ)/2
Geometric: Sₙ = a₁(rⁿ−1)/(r−1)
Identify type first: constant difference → arithmetic; constant ratio → geometric.
Unit 11
Binomial Theorem
(a+b)ⁿ = Σ C(n,k)aⁿ⁻ᵏbᵏ
C(n,k) = n!/(k!(n−k)!)
The term with bᵏ is the (k+1)th term. Match exponent of desired variable.
Unit 12
Conics — Parabola
y² = 4px → focus (p,0)
x² = 4py → focus (0,p)
p > 0 opens right/up; p < 0 opens left/down. Directrix is −p from vertex.
Unit 13
Conics — Ellipse
x²/a²+y²/b²=1, a>b
c² = a²−b²
foci: (±c, 0)
The larger denominator determines the major axis orientation.
Unit 14
Polar ↔ Rectangular
x = r·cos θ, y = r·sin θ
r² = x²+y², tan θ = y/x
Memorize: (r, θ) ↔ (r cos θ, r sin θ). Watch quadrant for θ.
Unit 15
Limits (Intro)
lim(x→a) [0/0]: factor & cancel
lim(x→∞) rational: leading terms
For 0/0 indeterminate forms, factor numerator/denominator and simplify.
Unit 16
Complex Numbers
(a+bi)(c+di) = (ac−bd)+(ad+bc)i
i² = −1
Use FOIL and replace i² with −1. Conjugate for division.
Unit 17
Matrices
det|a b; c d| = ad − bc
A⁻¹ = (1/det)·adj(A)
Matrix multiplication is not commutative. AB ≠ BA in general.
Unit 18
Vectors & Dot Product
u·v = u₁v₁+u₂v₂+u₃v₃
cos θ = (u·v)/(|u||v|)
Perpendicular ⟺ dot product = 0. Parallel ⟺ one is scalar multiple.
💡 Worked Examples
📘 Example A — Domain of a Function
Find the domain of \( f(x) = \dfrac{\sqrt{x-3}}{x-5} \)
  • Radicand must be non-negative: \(x - 3 \geq 0 \Rightarrow x \geq 3\)
  • Denominator cannot be zero: \(x - 5 \neq 0 \Rightarrow x \neq 5\)
  • Combine: \(x \geq 3\) AND \(x \neq 5\)
✅ Domain: \([3, 5) \cup (5, \infty)\)
📘 Example B — Exponential Equation
Solve: \(2^{2x-1} = 8^{x-2}\)
  • Rewrite with same base: \(8 = 2^3\), so \(8^{x-2} = 2^{3(x-2)} = 2^{3x-6}\)
  • Equate exponents: \(2x - 1 = 3x - 6\)
  • Solve: \(-1 + 6 = 3x - 2x \Rightarrow x = 5\)
✅ Answer: \(x = 5\)
📘 Example C — Trig Addition Formula
Find the exact value of \(\sin 75°\)
  • Write \(75° = 45° + 30°\)
  • Apply: \(\sin(A+B) = \sin A \cos B + \cos A \sin B\)
  • \(= \tfrac{\sqrt{2}}{2}\cdot\tfrac{\sqrt{3}}{2} + \tfrac{\sqrt{2}}{2}\cdot\tfrac{1}{2} = \tfrac{\sqrt{6}}{4} + \tfrac{\sqrt{2}}{4}\)
✅ Answer: \(\dfrac{\sqrt{6}+\sqrt{2}}{4}\)
1
Functions & Domain
What is the domain of \( f(x) = \dfrac{\sqrt{x-3}}{x-5} \)?
We need \(x - 3 \geq 0\) (radicand) giving \(x \geq 3\), and \(x - 5 \neq 0\) giving \(x \neq 5\). Combining: \([3, 5) \cup (5, \infty)\).
2
Composition of Functions
Given \(f(x) = 2x + 1\) and \(g(x) = x^2 - 3\), find \((f \circ g)(2)\).
\((f \circ g)(2) = f(g(2))\). First, \(g(2) = 4 - 3 = 1\). Then \(f(1) = 2(1) + 1 = 3\).
3
Inverse Functions
If \(f(x) = \dfrac{3x - 1}{x + 2}\), which of the following is \(f^{-1}(x)\)?
Set \(y = \frac{3x-1}{x+2}\). Then \(y(x+2) = 3x-1\), so \(xy + 2y = 3x - 1\), giving \(x(y-3) = -1 - 2y\), thus \(x = \frac{-(1+2y)}{y-3} = \frac{2y+1}{3-y}\). Replace \(y\) with \(x\): \(f^{-1}(x) = \dfrac{2x+1}{3-x}\).
4
Polynomial Functions
The polynomial \(p(x) = x^3 - 6x^2 + 11x - 6\) has three real roots. What is their sum?
By Vieta's formulas, the sum of roots of \(x^3 + bx^2 + \cdots\) is \(-b\). Here the coefficient of \(x^2\) is \(-6\), so sum \(= -(-6) = 6\). (The roots are \(1, 2, 3\) and \(1+2+3=6\).)
5
Rational Functions
Which best describes \(f(x) = \dfrac{x^2 - 4}{x^2 - x - 6}\)?
Factor: \(\dfrac{(x-2)(x+2)}{(x-3)(x+2)}\). The factor \((x+2)\) cancels, creating a hole at \(x = -2\). The remaining denominator \((x-3) = 0\) gives a vertical asymptote at \(x = 3\).
6
Exponential Equations
Solve for \(x\): \(2^{2x-1} = 8^{x-2}\)
Write \(8 = 2^3\), so \(8^{x-2} = 2^{3(x-2)} = 2^{3x-6}\). Setting exponents equal: \(2x - 1 = 3x - 6\), so \(x = 5\). Check: \(2^9 = 512 = 8^3\). ✓
7
Logarithmic Equations
Solve: \(\log_2 x + \log_2(x - 6) = 4\)
Combine: \(\log_2[x(x-6)] = 4\), so \(x(x-6) = 2^4 = 16\). This gives \(x^2 - 6x - 16 = 0\), factoring as \((x-8)(x+2) = 0\). So \(x = 8\) or \(x = -2\). Since \(\log_2(-2)\) is undefined, we reject \(x = -2\). Answer: \(x = 8\).
8
Trigonometry — Exact Values
What is the exact value of \(\sin 75°\)?
\(\sin 75° = \sin(45°+30°) = \sin 45°\cos 30° + \cos 45°\sin 30°\) \(= \tfrac{\sqrt{2}}{2}\cdot\tfrac{\sqrt{3}}{2} + \tfrac{\sqrt{2}}{2}\cdot\tfrac{1}{2} = \tfrac{\sqrt{6}}{4} + \tfrac{\sqrt{2}}{4} = \dfrac{\sqrt{6}+\sqrt{2}}{4}\).
9
Trigonometric Equations
Find all solutions of \(2\sin^2 x - \sin x - 1 = 0\) in \([0, 2\pi)\). How many solutions are there?
Factor: \((2\sin x + 1)(\sin x - 1) = 0\). So \(\sin x = -\tfrac{1}{2}\) giving \(x = \tfrac{7\pi}{6}, \tfrac{11\pi}{6}\); or \(\sin x = 1\) giving \(x = \tfrac{\pi}{2}\). Total: 3 solutions.
10
Law of Cosines
In triangle \(ABC\), \(a = 7\), \(b = 5\), and \(C = 60°\). Find \(c^2\).
Law of Cosines: \(c^2 = a^2 + b^2 - 2ab\cos C\). \(= 49 + 25 - 2(7)(5)\cos 60°\) \(= 74 - 70 \cdot \tfrac{1}{2} = 74 - 35 = 39\).
11
Arithmetic Sequences
An arithmetic sequence has first term \(a_1 = 3\) and common difference \(d = 4\). What is \(S_{10}\)?
\(a_{10} = 3 + (10-1)(4) = 3 + 36 = 39\). Then \(S_{10} = \frac{10}{2}(a_1 + a_{10}) = 5(3 + 39) = 5 \times 42 = 210\).
12
Geometric Series
A geometric sequence has \(a_1 = 2\) and common ratio \(r = 3\). Find \(S_5\).
\(S_5 = \dfrac{a_1(r^5 - 1)}{r - 1} = \dfrac{2(243 - 1)}{2} = \dfrac{2 \times 242}{2} = 242\).
13
Binomial Theorem
What is the coefficient of \(x^3\) in the expansion of \((x + 2)^5\)?
The term with \(x^3\) is \(\binom{5}{2} x^3 \cdot 2^2\). Here \(\binom{5}{2} = 10\) and \(2^2 = 4\). Coefficient \(= 10 \times 4 = 40\).
14
Polar Coordinates
Convert the polar point \(\left(3,\, \dfrac{\pi}{3}\right)\) to rectangular coordinates.
\(x = r\cos\theta = 3\cos\frac{\pi}{3} = 3 \cdot \frac{1}{2} = \frac{3}{2}\). \(y = r\sin\theta = 3\sin\frac{\pi}{3} = 3 \cdot \frac{\sqrt{3}}{2} = \frac{3\sqrt{3}}{2}\). Answer: \(\left(\frac{3}{2}, \frac{3\sqrt{3}}{2}\right)\).
15
Conics — Parabola
For the parabola \(y^2 = 12x\), what is the focus?
Standard form \(y^2 = 4px\). Here \(4p = 12\), so \(p = 3\). For this orientation the focus is at \((p, 0) = (3, 0)\) and the directrix is \(x = -3\).
16
Conics — Ellipse
For the ellipse \(\dfrac{x^2}{25} + \dfrac{y^2}{9} = 1\), where are the foci?
\(a^2 = 25, b^2 = 9\). So \(c^2 = a^2 - b^2 = 25 - 9 = 16\), giving \(c = 4\). Since \(a^2 > b^2\) along the \(x\)-axis, foci are at \((\pm 4, 0)\).
17
Limits
Evaluate: \(\displaystyle\lim_{x \to 2} \frac{x^2 - 4}{x - 2}\)
The form \(\frac{0}{0}\) is indeterminate. Factor: \(\frac{(x-2)(x+2)}{x-2} = x + 2\) for \(x \neq 2\). Taking the limit: \(\lim_{x\to 2}(x+2) = 4\).
18
Complex Numbers
Simplify \((3 + 2i)(1 - 4i)\).
FOIL: \(3(1) + 3(-4i) + 2i(1) + 2i(-4i)\) \(= 3 - 12i + 2i - 8i^2\). Since \(i^2 = -1\): \(= 3 - 10i - 8(-1) = 3 - 10i + 8 = 11 - 10i\).
19
Matrices — Determinant
Find the determinant of \(A = \begin{pmatrix} 2 & 3 \\ 1 & 4 \end{pmatrix}\).
\(\det(A) = ad - bc = (2)(4) - (3)(1) = 8 - 3 = 5\).
20
Vectors — Dot Product
Given \(\mathbf{u} = \langle 2, -1, 3 \rangle\) and \(\mathbf{v} = \langle 4, 2, -1 \rangle\), what is \(\mathbf{u} \cdot \mathbf{v}\)?
\(\mathbf{u} \cdot \mathbf{v} = (2)(4) + (-1)(2) + (3)(-1) = 8 - 2 - 3 = 3\).
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